Meeting Rooms (Conflict Check)

Given meeting intervals, decide if one person can attend all of them with no overlap; an end time equal to the next start is not a conflict. Problem Requirements You are given a list of meeting time intervals. Each interval has a specific start time and end time. Your task is to check if a person can attend all the meetings in the list. This is only possible if there are no time conflicts (overlaps) between any of the meetings. Note: If one meeting ends at the exact same time the next one starts (for example, one ends at 8 and the next starts at 8), this is not considered a conflict. Sample Cases Case 1: Input: intervals = [(0,30),(5,10),(15,20)] Output: false Reasoning: The meeting (0,30) overlaps with (5,10). The meeting (0,30) also overlaps with (15,20). Case 2: Input: intervals = [(5,8),(9,15)] Output: true Input Limits The list will contain between 0 and 500 meetings (0 <= intervals.length <= 500). Start and end times will be between 0 and 1,000,000.